MCQ - TNPSC JTO
JTO - 538 - Industrial Robotics and Digital Manufacturing
538 - Unit III Knowledge of Industrial Engineering Drawing
193)
Nominal 100 mm with tolerance ±0.02 mm. What are upper and lower limits?
A.
B.
C.
D.
194)
A hole 20.00 H8 (H8 = +0.033 / 0.000). Shaft 20.00 f7 (f7 = −0.025 / −0.043). Determine maximum interference (positive means interference).
A.
B.
C.
D.
195)
Shaft 15.00 mm with limits +0.010 / −0.005. What is the tolerance and mean size?
A.
B.
C.
D.
196)
A shaft is specified 12.00 ±0.02 and mating hole is 12.05 ±0.03. Minimum clearance = ?
A.
B.
C.
D.
197)
Determine total tolerance if upper deviation = +0.040 and lower deviation = −0.010.
A.
B.
C.
D.
198)
Hole 75.00 +0.15/0.00 mm, shaft 75.00 −0.05/−0.20 mm. What is maximum clearance?
A.
B.
C.
D.
199)
A nominal dimension 60 mm with unilateral tolerance of +0.06/0.00. What is percentage tolerance relative to nominal?
A.
B.
C.
D.
200)
A dimension chain: A = 20.00 ±0.02, B = 30.00 ±0.03. Worst-case sum tolerance for A+B = ?
A.
B.
C.
D.